Amysterious compoud with the chemical formula mx (ksp 1.27x10-36) is present in two different solutions. what is its molar solubility in 0.25 m m2so4?

The molar solubility of MX is

Explanation:

We are given:

The chemical equation for the ionization of MX follows:

                  S         S

The expression of for above equation is:

     ......(1)

The chemical equation for the ionization of follows:

 0.25M           0.5M      0.25M

Total concentration of cation from both the equation is:

As, , so S is also very very less than 1 and can be easily neglected.

So,

Putting values in equation 1, we get:

Hence, the molar solubility of MX is

the density of gold = 19.3 g/cm3

the relation between density and mass and volume is

density = mass / volume

given :

mass of gold = 13 g

density = 13g / volume = 19.3

volume = 13 /19.3 = 0.67 cm^3

thus volume of gold nugget = 0.67 cm^3