Aperson suffering from hyponatremia has a sodium ion concentration in the blood of 0.116 m and a total blood volume of 4.7 l . part a what mass of sodium chloride would need to be added to the blood to bring the sodium ion concentration up to 0.139 m, assuming no change in blood volume?

Explanation:

Normal moles of = volume × normal concentration

                              = 4.7 × 0.139 = 0.6533 mol

Moles of in hyponatremia blood = volume × hyponatremia concentration

                              = 4.7 × 0.116 = 0.5452 mol

Moles of NaCl to be added = moles of extra needed

                            = 0.6533 mol - 0.5452 mol = 0.1081 mol

Mass of NaCl = moles × molar mass of NaCl

                        = 0.1081 mol × 58.443

                        = 6.317g

                        = 6.32 g (approx)

Thus, we can conclude that mass of sodium chloride would need to be added to the blood is 6.32 g.                    

dynamic equilibrium is the answer.

i would say b

explanation:

but i think i would need more information than that