What is the energy released in the fission reaction 1 0 n + 235 92 u → 131 53 i + 89 39 y + 16 1 0 n 0 1 n + 92 235 u → 53 131 i + 39 89 y + 16 0 1 n ? (the atomic mass of 131 i 131 i is 130.9061246 u and that of 89 y 89 y is 88.9058483 u)

The energy released in the given nuclear reaction is 94.99 MeV.

Explanation:

For the given nuclear reaction:

We are given:

Mass of = 235.043924 u

Mass of = 1.008665 u

Mass of = 130.9061246 u

Mass of = 88.9058483 u u

To calculate the mass defect, we use the equation:

Putting values in above equation, we get:

To calculate the energy released, we use the equation:

 (Conversion factor:    )

Hence, the energy released in the given nuclear reaction is 94.99 MeV.

"you start with 15.67 g mgco3-xh2o, when heated and all the water is removed, you are left with 7.58 g mgco3 only.

therefore, you had 15.67 - 7.58 = 8.09g h2o  

moles of each :

7.58g mgco3 = ? moles = 7.58g / 83.4g/mole = 0.09moles  

8 09g h2o = ? moles = 8.09g / 18g/mole = 0.44moles  

molar ratio between the two by dividing both numbers by the smallest number :

0.09 / 0.09 = 1  

0.44 / 0.09 = 4.8  

mgco3-5h2o"