***30
if 25.0 ml of a 0.100 m aqueous sodium hydroxide is mixed with 25.0 ml of a 0.100 m aqueous hydrochloric acid in a calorimeter at an initial temperature of 23.0 degrees celsius, what is the enthalpy change of this reaction if the final temperature reached in the calorimeter is 25.5 degrees celsius?
naoh + hcl yields nacl + h2o

Approximately 241 kJ/mol reaction.

Explanation:

How many moles of the reaction took place?

The coefficient in front of both NaOH and HCl are both one. In other words, one mole of the reaction will require one mole of NaOH and one mole and HCl.

of both NaOH and HCl are available. As a result, 0.0025 moles of the reaction would have taken place.

How much heat was produced?

Approximate volume of the solution:

.

Approximate mass of the solution:

.

Enthalpy change per mole reaction:

.

n+h→nh3

we must remember that nitrogen and hydrogen are both diatomic molecules in their standard gas form. this adjusts the equation to

n2+h2→nh3

now we need to adjust coefficients in order to balance the atoms on each side of the equation. currently we have 2 atoms of nitrogen and 2 atoms of hydrogen on the reactant side and 1 atom of nitrogen and 3 atoms of hydrogen on the product side.

we can balance the hydrogens by placing a coefficient of 2 in front of ammonia and a coefficient of 3 in front of the hydrogen.

n2+3h2→2nh3

this gives us 6 hydrogen on each side and coincidentally the nitrogens now equal 2 on each side.

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hope i !