Pd-99 has a half-life of 22.3 hours. how many grams of a 89.8 gram sample would have decayed after exactly three half-lives?

78.875 g

Explanation:

First half life is the time at which the concentration of the reactant reduced to half.

Second half reaction is the time at which the remaining concentration reduced to half or the initial concentration reduced to 1/4.

Third half life is the time at which the remaining concentration reduced to half or the initial concentration reduced to 1/8.

The initial mass of the sample = 89.8 g

After 3 half-lives, the mass should reduce to 1/8.

So the concentration left = 1/8 of 89.8 g = 11.225 g

So, the mass of the sample decayed = 89.8 g - 11.225 g = 78.875 g

11.23 grams

Explanation:

Answer via Educere/ Founder's Education

a) the particles of the chair are strongly held together.

the formula for the conversion of temperature from degree celsius to kelvin is:

the sample of water at is converted to kelvin temperature by using the above formula as:

on comparing the two samples of water at or we can say that at and at respectively. the difference between the temperatures of two samples of water is:

hence, one can say that the sample of water at is greater than the sample of water at by .