The equilibrium constant, kp, for the following reaction is 10.5 at 350k.2ch2cl2(g) image for the equilibrium constant, kp, for the following reaction is 10.5 at 350k. 2ch2cl2(g) pcl3(g) + cl2(g) if ch4(g) + ccl4(g)if an equilibrium mixture of the three gases in a 17.1 l container at 350k contains ch2cl2 at a pressure of 0.401 atm and ch4 at a pressure of 0.470 atm, the equilibrium partial pressure of ccl4 is atm.2. consider the following reaction: pcl5(g) image for the equilibrium constant, kp, for the following reaction is 10.5 at 350k. 2ch2cl2(g) pcl3(g) + cl2(g) if pcl3(g) + cl2(g)if 6.60e-2 moles of pcl5, 0.340 moles of pcl3, and 0.307 moles of cl2 are at equilibrium in a 14.7 l container at 561 k, the value of the equilibrium constant, kp, .

a polar bond is formed when electrons are shared unevenly between atoms

so what is the problem with your lab report and whats the subject of the lab report? i will you

answer : (a) volume of the gas = 8.67 ×   l

                (b) second virial coefficient b = -1.21226 l/mole

solution :   given,     t = 300k

                                p = 20atm

                                z = 0.86

                                n = 8.2 mmoles = 8.2 × moles

                                r =   0.082 l atm/k/mol

        find,     (a) volume of gas   and (b) second virial coefficient b at 300k.

formula used :            

                          and            

(a)            

                    = \times 0.082\times 300}{20}[/tex]

                    = 8.67 ×   l

(b)      

                    = (0.00867-1) × 8.659

                    = - 8.5839 l/mole