Balance the equation and show the calculation of the number of moles and grams of co2 formed from 11.9 grams of o2. show your answers to 3 significant figures. c6h14 + o2 → co2 + h2o

0.2349 moles, 10.3356 g

Explanation:

The given reaction is :

The balanced reaction by equating the same number of each atom both side is :

Given that :

Amount of oxygen gas = 11.9 g

Molar mass of oxygen gas = 32 g/mol

The formula for the calculation of moles is shown below:

Thus, moles are:

From the reaction,  

19 moles of oxygen gas on reaction forms 12 moles of carbon dioxide

Also,

1 mole of oxygen gas on reaction forms 12/19 moles of carbon dioxide

So,

0.3719 moles of zinc on reaction forms mole of carbon dioxide

Moles of carbon dioxide formed = 0.2349 moles

Mass of carbon dioxide = moles×Molar mass

Molar mass of carbon dioxide = 44 g/mol

Mass of carbon dioxide formed = 0.2349 ×44 g = 10.3356 g

"the periodic table is arranged in order of atomic number."