Answers: 2
![[Ag^{+}]=4.2\times 10^{-2}M](/tpl/images/0203/2904/66458.png)
![Ksp=[Ba^{2+}][CrO_{4}^{2-}]](/tpl/images/0203/2904/e5293.png)
![1.2\times 10^{-10}=(0.20)[CrO_{4}^{2-}]](/tpl/images/0203/2904/1abbf.png)
![[CrO_{4}^{2-}]=\frac{1.2\times 10^{-10}}{(0.20)}= 6.0\times 10^{-10}](/tpl/images/0203/2904/36368.png)
![Ksp=[Ag^{+}]^{2}[CrO_{4}^{2-}]](/tpl/images/0203/2904/cc1c4.png)
![1.1\times 10^{-12}=[Ag^{+}]^{2}](6.0\times 10^{-10})](/tpl/images/0203/2904/6275b.png)
![[Ag^{+}]^{2}]=\frac{1.1\times 10^{-12}}{(6.0\times 10^{-10})}= 1.8\times 10^{-3}](/tpl/images/0203/2904/6515a.png)
![[Ag^{+}]=\sqrt{1.8\times 10^{-3}}=4.2\times 10^{-2}M](/tpl/images/0203/2904/8e3b4.png)
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0.10 m potassium chromate is slowly added to a solution containing 0.20 m agno3 and 0.20 m ba(no3)2....
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