The electron configuration of a particular diatomic species is (σ2s)2(σ*2s)2(σ2p)2(π2p)4(π*2p)4. what is the bond order for this species?

The diatomic species has bond order equal to 1

Explanation:

Bond order = (number of bonding electrons-number of antibonding electrons)

Here , \sigma_{2p} and are bonding orbitals. and are antibonding orbitals.

So total number of bonding electrons = (2+2+4) = 8

So total number of antibonding electrons = (2+4) =6

Hence bond order =

So, the diatomic species has bond order equal to 1.

the correct answer would be d. hope this !