In a particular experiment at 300°c, [no2] drops from 0.0100 to 0.00650 m in 100 s. the rate of appearance of o2 for this period is m/s.

Rate of appearance of O2 = 1.75*10^-5 M/s

Explanation:

NO2 decomposes to O2 as:

2NO2  → 2NO + O2

minus sign signifies that NO2 disappear in the reaction.

Where,

Initial concentration of NO2 = 0.0100 M

After 100 s concentration of NO2 = 0.00650 M

Change in concentration of NO2 = (0.0100 - 0.00650)M

                                                       = 0.0035 M