If i have 1.9 moles of gas held at a pressure of 4.95 atm and in a container with a volume of 5000.0 ml, what is the temperature of the gas?

158.66 K

Explanation:

Given that:

Moles of the gas = 1.9 moles

Pressure = 4.95 atm

Volume = 5000.0 mL

Also, 1 mL = 10⁻³ L

So, volume = 5 L

Using ideal gas equation as:

PV=nRT

where,

P is the pressure

V is the volume

n is the number of moles

T is the temperature

R is Gas constant having value = 0.0821 L.atm/K.mol

Applying the equation as:

4.95 atm × 5 L=1.9 moles × 0.0821 L.atm/K.mol × T

⇒T = 158.66 K

2fe + 3h2so4 -> fe2(so4)3 + 3h2

it is necessary to balance equations in order to get the proper amount of reactants as well as products in order not to make a miscalculation.

you cannot change the subscripts as that would change the substance itself. for instance, diatomic elements such as h2 only have the subscript two when a gas. another example would be so4, if you were to change the subscript, the element would no longer be sulfate.

we change the coefficients instead as that only changes the number of molecules rather than the substance itself.

hope this !