What is the potential of a cell made up of zn/zn2+ and cu/cu2+ half-cells at 25ºc if [zn2+] = 0.25 m and [cu2+] = 0.15 m?

Cell potential = +1.09V

Explanation:

Given:

[Zn2+] = 0.25 M

[Cu2+]  = 0.15 M

In this electrochemical cell, Zn/Zn2+ half cell will serve as the anode and Cu/Cu2+ will act as the cathode.

The two half reactions and the reduction potentials based on the standard reduction potential chart are:

Anode (Oxidation):

.......E°(anode) = -0.76 V

Cathode(Reduction):

........E°(cathode)= +0.34 V

Overall reaction:

Based on the Nernst equation:

in scientific notation, the value of the  speed of light in a vacuum

  will be written as 2.995 * 10^8. when this value is represented in the form of

  a * 10^b, then, a = 2.995 and b = 8.

the value of the speed of light in a vacuum given above can also be rounded up to approximately 300000000. in this case, the scientific notation will be written as 3 *10^8.