Consider the following equilibrium. 2 so2 (g) o2 (g) 2 so3 (g) the equilibrium cannot be established when is/are placed in a 1.0-l container. a) 0.75 mol so2 (g) b) 0.25 mol of so2 (g) and 0.25 mol of so3 (g) c) 1.0 mol so3 (g) d) 0.50 mol o2 (g) and 0.50 mol so3 (g) e) 0.25 mol so2 (g) and 0.25 mol o2 (g)

Answer : The correct option is (A) 0.75 mol

Explanation :

The given equilibrium reaction is,

From the given reaction we conclude that, the equilibrium cannot be established when there is only one reactant's amount present that means the amount of both the reactants are necessary for the formation of product.

As per question,

(A) 0.75 mol

The equilibrium cannot be established because   needs to form .

(B) 0.25 mol of and 0.25 mol of

The equilibrium can be established because    can decompose to form  .

(C) 1.0 mol

The equilibrium can be established because    can decompose to form    and  .

(D) 0.50 mol and 0.50 mol

The equilibrium can be established because    can decompose to form   .

(E) 0.25 mol and 0.25 mol

The equilibrium can be established because    and   can react to form .

Hence, the correct option is (A) 0.75 mol

- both b and d.

-since b and d are the closest coastlines then that makes it the most affected.

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