600 s after initiation of a first order reaction 48.5% of the initial reactant concentration remains present. what is the rate constant for this reaction?

Explanation:

For a first order reaction the rate law is:

Integranting both sides of the equation we get:

where "a" stands for [A] (molar concentration of a given reagent) and "b" is {A]0 (initial molar concentration of a given reagent), "t" is the time in seconds.

From that integral we get the integrated rate law:

therefore k is

answer: cellular respiration takes in food and uses it to create atp, a chemical which the cell uses for energy. usually, this process uses oxygen, and is called aerobic respiration. it has four stages known as glycolysis, link reaction, the krebs cycle, and the electron transport chain.