Given that the molar mass of h2o is 18.02g/mol, how many liters of propane are required at stp to produce 75 g of h2o from this reaction?

C₃H₈ + 5O₂ = 3 CO₂ + 4 H₂O

44.1 g 4* 18.02 g

? g 75 g

mass of C₃H₈ = 75 * 44.1 / 4 * 18.02

mass of C₃H₈ = 3307.5 / 72.08

= 45.886 g of propane

water is used to store them because it would keep the radiation from getting out in the open and causing harm to the workers

- lead + phosphoric acid = hydrogen + lead(ii) phosphate