Given the relationship between the standard cell potential (ecell) and equilibrium constant (k) for a ink, where r is ideal gas consta nt 8.314 j rt redox reaction occurring in the cells is given by: ecell mol-; t is temperature in kelvins (i. e. 25 °c 298.15 k); and f is faradays constant 96,485 c mol nf referring to the provided table of electrode potentials, calculate the equilibrium constant k for the oxidation of copper in the following reaction: cu (s) +2 h* (aq)cu(aq) +h2 (g) (5 marks)

first, consult an activity series chart to determine if al is more reactive than fe. it is, so it will replace the fe. now, one can continue with the problem.

next, make sure you have a correctly balanced equation.

3feo + 2al ==> 3fe + al2o3

now, determine which reactant (feo or al) is in limiting supply.

moles feo present = 125 g x 1 mole/71.8 g = 1.74 moles

moles al present = 25.0 g x 1 mole/26.98 g = 0.927 moles

since from the balanced equation, it take 3 mol feo for every 2 mol al, al will be limiting.

you can determine this simply by dividing moles of each by their coefficient in the balanced equation. for example: 1.74/3 = 0.58 and 0.927/2 = 0.464. al is less, so it is limiting.

finally, using the stoichiometry in the balanced eq. determine mass of fe that can be produced from 0.927 moles of al.

0.927 moles al x 3 moles fe/2 moles al x 55.8 g/mole = 77.6 g

the product of the pressure and volume is also constant

d) nh3 give me brainliest