The combustion of octane is given in this reaction 2c8h18++18h2 o, identify the limit reagent for this reaction with respect of carbon dioxide given starting mass of 12.85g of octane and 7.46g of oxygen.

Liming reagent in the given reaction is oxygen.

Explanation:

Mass of octane = 12.85 g

Mass of oxygen = 7.46 g

Molar mass of octane = 114.23 g/mol

Molar mass of oxygen = 32

According to the reaction, 2 moles of octane requires 25 moles of O2

so, 0.1125 moles of octane requires of oxygen.

but only 0.2331 mol of oxygen is present.

Hence, oxygen is the limiting reagent

answer: c.

explanation: