How much energy is released by the decay of 3 grams of 20th in the following reaction 230 th - 226ra + 'he (230 th = 229.9837 g/mol, 226ra - 225.9771 g/mol, "he = 4.008 g/mol) (10 pts.)

Answer : The energy released by the decay of 3 grams of 'Th' is

Explanation :

First we have to calculate the mass defect .

The balanced reaction is,

Mass defect = Sum of mass of product - sum of mass of reactants

conversion used :

Now we have to calculate the energy released.

The energy released is

Now we have to calculate the energy released by the decay of 3 grams of 'Th'.

As, 230 grams of Th release energy =

So, 3 grams of Th release energy =

Therefore, the energy released by the decay of 3 grams of 'Th' is