Asolution contains 20.0 g of c6h12o6 (glucose) in 250 g. of water.

a. what is freezing point depression of solvent?

The freezing point depression of solvent is 0.8265 K.

Explanation:

Mass of glucose = 250 g

Mass of solvent = 20.0 g = 0.020 kg

Molal depression water constant of water, = 1.86 K kg/mol

Molality of the solution =

Normal freezing point of water =

Freezing point of solution =

The freezing point depression of solvent is 0.8265 K.

the correct answer is b. a strong acid completely dissociates to its ions when dissolved in water. completely dissociates to and ions. a is incorrect because does not fully ionize to and ions and some remain as the compound . c and d are incorrect because, and do not fall into the category of bronsted lowry acids. a bronsted lowry acid is a proton donor and since both molecules do not have a proton to donate they are not bronsted lowry acids. likewise,   if we use the lewis acid definition, they cannot be acids. a lewis acid is an electron pair acceptor. both and have a complete octet so can not accept any electrons which disqualifies them as acids.

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