Consider this question: what is the molarity of kmno4 in a solution of 0.0908 g of kmno4 in 0.500 l of solution?
(a) outline the steps necessary to answer the question
(b) answer the question

0.0011 M.

Explanation:

Molarity of a substance , is the number of moles present in a liter of solution .

M = n / V

M = molarity

V = volume of solution in liter ,

n = moles of solute ,

Moles is denoted by given mass divided by the molecular mass ,

Hence ,

n = w / m

n = moles ,

w = given mass ,

m = molecular mass .

From the question ,

w = given mass of KMnO₄ = 0.0908 g

and ,

V = 0.500 L

Since ,

we know ,

m = Molecular mass of   KMnO₄ =  158 g/mol

using , the above formula to calculate the moles ,

n = w / m = 0.0908 g / 158 g/mol = 0.00057 mol

now , calculating the molarity as ,

M = n / V =  0.00057 mol / 0.500 L = 0.0011 M.

water and alcohols have similar properties because water molecules contain hydroxyl groups that can form hydrogen bonds with other water molecules and with alcohol molecules, and likewise alcohol molecules can form hydrogen bonds with other alcohol molecules as well as with water.