If 4.12 l of 0.85-m h3po4 solution is be diluted to a volume of 10.00 l, what is the concentration resulting solution

The concentration resulting solution = 0.350 M

Explanation:

In case of dilution , the following formula can be used -

M₁V₁ = M₂V₂

where ,

M₁ = initial concentration ,

V₁ = initial volume ,

M₂ = final concentration , i.e. , concentration after dilution ,

V₂ = final volume .

from , the question ,

M₁ = 0.85 M

V₁ = 4.12 L

M₂ = ?

V₂ = 10.0 L

Using the above formula , the molarity of the final solution after dilution , can be calculated as ,

M₁V₁ = M₂V₂

0.85 M * 4.12 L =  M₂ * 10.0 L

M₂ = 0.85 M * 4.12 L  / 10.0 L

M₂ = 0.350 M