What volume of a 0.20-m k2so4 solution contains 57 g of k2so4?

1.635 L

Explanation:

Molarity of a substance , is the number of moles present in a liter of solution .

M = n / V

M = molarity  

V = volume of solution in liter ,

n = moles of solute ,

Moles is denoted by given mass divided by the molecular mass ,  

Hence ,  

n = w / m

n = moles ,  

w = given mass ,  

m = molecular mass .

From the question ,

Molarity of  K₂SO₄ = 0.20 M

given mass of  K₂SO₄ = 57 g

Since , the molecular mass of  K₂SO₄ = 174 g /mol

Using the above formula , moles can be calculated as -

n = w / m  =  57 g / 174 g /mol = 0.327 mol

The volume is calculated by using the above formula ,

M = n / V

V = n / M

V =   0.327 mol / 0.20 M = 1.635 L

im not exactly sure but i think its b!