Use the following half-reactions to construct a voltaic cell:
cr3+(aq) + 3e−\rightarrow→ cr(s) eo = −0.73 v
ag+(aq) + e−\rightarrow→ ag(s) eo = 0.80 v
determine the balanced overall redox reaction, and calculate eocell.
3 ag(s) + cr3+(aq) \rightarrow→ 3 ag+(aq) + cr(s), eocell = −1.53 v
3 ag+(aq) + cr(s) \rightarrow→ 3 ag(s) + cr3+(aq),eocell = +3.13 v
3 ag(s) + cr3+(aq) \rightarrow → 3 ag+(aq) + cr(s), eocell = −3.13 v
ag(s) + cr3+(aq) \rightarrow→ ag+(aq) + cr(s), eocell = −1.53 v
3 ag+(aq) + cr(s) \rightarrow→ 3 ag(s) + cr3+(aq), eocell = +1.53 v
ag+(aq) + cr(s) \rightarrow→ ag(s) + cr3+(aq), eocell = +1.53 v

The correct answer is

Explanation:

We are given:

The substance having highest positive potential will always get reduced and will undergo reduction reaction. Here, silver will always undergo reduction reaction will get reduced.

Chromium will undergo oxidation reaction and will get oxidized.

The half reactions for the above cell is:

Oxidation half reaction:

Reduction half reaction:       ( × 3)

Net equation:  

Oxidation reaction occurs at anode and reduction reaction occurs at cathode.

To calculate the of the reaction, we use the equation:

Putting values in above equation, we get:

Hence, the correct answer is

metals are good conductor of electricity. it has free electrons on their surface. according to electron pool theory, each atom present in a metal crystal losses all of its valence electron and as a result a pool of free is form. these pool of electrons are free to move and   conduct electricity easily   while making metal as good conductor.

the correct answer is a. the ability of electrons to flow throughout the metal.

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