Copper(i) iodine (cul) is often added to the table salt as a dietary source of iodine. how many moles of cul are contained in 1.00 lb (454 g) of table salt containing 0.0100% by mass?

0.238 millimoles

Explanation:

Given:

Mass of the table salt = 1.00 lb = 454 g

Copper(I) Iodine (cul) present in the table = 0.0100% by mass

or

Copper(I) Iodine (cul) present in the 1 pound of salt = 0.01% of 454 g

= 0.0454 grams

Molar mass of the CuI = 63.54 grams + 126.90 grams = 190.44 grams

Thus,

the number of moles of CuI present in 1 pound of salt = Mass / Molar mass

= 0.0454 / 190.44

= 2.38 × 10⁻⁴ moles

= 0.238 millimoles

in the analysis of systems that involve fluid flow, we frequently encounter the combination of properties u and pv.

c. is the answer

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