Complete and balance the following acid-base equations:
(a)hcl gas reacts with solid ca(oh)2
(b)a solution of sr(oh)2 is added to the solutionn of hno3.

Hey there!:

a) 2 HCl  + Ca(OH)₂ = CaCl₂ + 2 H₂O

2 moles of HCl reacts with 1 mole of calcium hydroxide  it forms calcium chloride ,  which is precipitate and forms water  

b) Sr(OH)₂ + 2 HNO₃ = Sr(NO₃)₂ + 2 H₂O

One mole of strontium hydroxide reacts with 2 moles of nitric acid produces strontium nitrate and water as shown above  

* Acids are  HCl and HNO₃  and bases are Ca(OH)₂  and Sr(OH)₂

I hope this will help !!

given:

mass of na = 115 g

excess cl2

to determine:

mass of nacl produced

explanation:

given reaction is-

2na(s) + cl2(g) → 2nacl(s)

since cl2 is in excess, na will be the limiting reagent

as per the reaction stoichiometry na: nacl = 1: 1

i.e. moles of na reacted = moles of nacl formed

now, # moles of na = mass of na/atomic mass

                                  = 115 g/23 g.mol-1 = 5 moles

therefore, moles of nacl = 5

molar mass of nacl = 58 g/mol

mass of nacl = 5 moles * 58 g.mol-1 = 290 g

ans: amount of nacl produced = 290 g