Asample of gallium bromide gabr2,weighing 0.165 g was dissolved in water and treated with silver nitrate agno3, and resulting the precipitation of 0.299 g agbr. use this data to compute the %ga (by mass) gabr2

The percent gallium in gallium bromide is 30.30 %.

Explanation:

To calculate the number of moles, we use the equation:

    .....(1)

Given mass of gallium bromide = 0.165 g

Molar mass of titanium gallium bromide = 229.53 g/mol

Putting values in equation 1, we get:

The chemical equation for the reaction of gallium bromide and silver nitrate follows:

By Stoichiometry of the reaction:

1 moles of gallium bromide produces 1 mole of gallium nitrate

So, 0.00072 moles of gallium bromide will produce = of gallium nitrate

Now, calculating the mass of gallium nitrate from equation 1, we get:

Molar mass of gallium nitrate = 193.73 g/mol

Moles of gallium nitrate = 0.00072 moles

Putting values in equation 1, we get:

Calculating the mass of gallium in the reaction, we use unitary method:

In 1 mole of gallium nitrate, 1 mole of gallium atom is present.

In 193.73 grams of gallium nitrate, 69.72 g of gallium atom is present.

So, in 0.139 grams of gallium nitrate, the mass of gallium present will be =

To calculate the percentage composition of gallium in gallium bromide, we use the equation:

Mass of gallium bromide = 0.165 g

Mass of gallium = 0.050 g

Putting values in above equation, we get:

Hence, the percent gallium in gallium bromide is 30.30 %.

Nonmetals usually react by gaining electrons

The answer to the question is d