5k + kno3 3k2o + n
how much in grams would you need of each reactant to make 27 lbs of nitrogen?

174,957.143 grams of potassium and 89,228.478 grams of potassium nitrate will be needed.

Explanation:

Mass of nitrogen =  27 lbs = 12,247 g

1 lbs = 453.592 g

Moles of nitrogen =

According to reaction, 1 mole of nitrogen is produced from 5 moles of potassium and 1 mole of potassium nitrate.

Then 874.786 mol of nitrogen will be obtained from :

of potassium.

Then 874.786 mol of nitrogen will be obtained from :

of potassium nitrate.

Mass of 4,373.928 moles of potassium:

of potassium

Mass of 874.789 moles of potassium nitrate:

of potassium nitrate

< > according to newton's third law of motion, forces always act in equal but opposite pairs. another way of saying this is for every action, there is an equal but opposite reaction.< >

gas

explanation:

smoke is the matter of a gas