If 14.5 kj of heat were added to 485 g of liquid water, how much would its temperature increase?

The increase in temperature is 7.14°C

Explanation:

To calculate the change in temperature, we use the equation:

where,

q = heat absorbed = 14.5 kJ = 14500 J    (Conversion factor: 1 kJ = 1000 J)

m = mass of water = 485 g g

c = specific heat capacity of water = 4.184 J/g.°C

= change in temperature = ?

Putting values in above equation, we get:

Hence, the increase in temperature is 7.14°C

hloride, what is the mass of calcium in

explanation:

1. for the first question, we must find the mass of the anhydrous salt, mgso₄. the molar mass for mgso₄·7h₂o is 246.47 g/mol, while that of mgso₄ is 120.37 g/mol.7.834 g mgso₄·7h₂o * 1 mol mgso₄·7h₂o/246.47 g * 1 mol mgso₄/1 mol mgso₄·7h₂o * 20.37 g mgso₄/mol = 0.647 g mgso₄

2. mass of water = mass of sample - mass of anhydrous salemass of water = 7.834 - 0.647 = 7.19 gpercent water in hydrate = 7.19/7.834 * 100 = 91.74%