Procaine hydrochloride (mw = 273) is a 2-ion electrolyte, dissociating 80%. calculate its dissociation factor. round to tenths place.

Dissociation factor = 1.8

Explanation:

Data provided in the question:

Molecular weight of the Procaine hydrochloride = 273

Number of ions contained, n = 2

Fraction Dissociating, α = 80% = 0.8

Now,

the  dissociation factor 'i' is given as:

i = 1 + α × ( n - 1 )

on substituting the respective values, we get

i = 1 + 0.8 × ( 2 - 1 )

or

i = 1 + ( 0.8 × 1 )

or

i = 1.8

"you start with 15.67 g mgco3-xh2o, when heated and all the water is removed, you are left with 7.58 g mgco3 only.

therefore, you had 15.67 - 7.58 = 8.09g h2o  

moles of each :

7.58g mgco3 = ? moles = 7.58g / 83.4g/mole = 0.09moles  

8 09g h2o = ? moles = 8.09g / 18g/mole = 0.44moles  

molar ratio between the two by dividing both numbers by the smallest number :

0.09 / 0.09 = 1  

0.44 / 0.09 = 4.8  

mgco3-5h2o"

it forms an anion that has a larger radius. anions have a negative charge and are larger than the original atom.