Amonolayer containing 3.19 × 10 –6 g of oleic acid has an area of 20.0 cm 2. the density of oleic acid is 0.895 g / ml. what is the thickness of the monolayer (the length of an oleic acid molecule)?

1.78 × 10⁻⁷ cm

Explanation:

Using,

Density = Mass / Volume

Given:

Area = 20.0 cm²

Density = 0.895 g/mL

Mass = 3.19 × 10⁻⁶ g

Applying in the density formula as:

0.895 g/mL = 3.19 × 10⁻⁶ g / Volume (ml)

Volume = 3.56  × 10⁻⁶  mL

Since, 1 mL = cm³

So, Volume = 3.56  × 10⁻⁶  cm³

Thickness (height) of monolayer = ?

Also, Volume = area x thickness

So,

Thickness = Volume/Area = 3.56  × 10⁻⁶ cm³ / 20.0 cm² = 1.78 × 10⁻⁷ cm

at the bottom

explanation:

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