Saved propane burns in air according to the equation c3ha(g 502lg)3co2) + 4h20(g) what volume of o2 in liters would be required if 15.0 l of propane burns, assuming that all of the gases are under the same conditions? short answer toolbar navigation e i e b ius ea this question will be sent to your instructor for grading. 20 of 25 l next > prev nere to search

75 liters of in liters would be required if 15.0 L of propane burns, assuming that all of the gases are under the same conditions.

Explanation:

According to avogadro's law, 1 mole of every substance occupies 22.4 Lat STP and contains avogadro's number of particles.

To calculate the number of moles, we use the equation:

According to stoichiometry:

1 mole of propane combines with = 5 moles of oxygen

Thus 0.67 moles of propane combine with  =

Volume of

Thus 75 liters of in liters would be required if 15.0 L of propane burns, assuming that all of the gases are under the same conditions.

answers: to make sure that all of the broken pieces of tablet were added to the water, to allow for fair comparison of all three trials, with different particle sizes to avoid experimental error