How many liters of 1.0 m hcl do you need to neutralize 2.0 l of 3.0 m naoh? how many liters of 1.0 m hcl do you need to neutralize 1.5 l of 3.0 m ca(oh)2? how many liters of 1.0 n h2so4 do you need to neutralize 1.5 liters of 3.0 n sr(oh)2?

For 1: The volume of HCl required is 6 L.

For 2: The volume of HCl required is 9 L.

For 3: The volume of sulfuric acid required is 4.5 L.

Explanation:

To calculate the volume of acid, we use the equation given by neutralization reaction:

       ......(1)

where,

are the n-factor, molarity and volume of acid

are the n-factor, molarity and volume of base

We are given:

Putting values in equation 1, we get:

Hence, the volume of HCl required is 6 L.

We are given:

Putting values in equation 1, we get:

Hence, the volume of HCl required is 9 L.

To calculate the volume of acid, we use the equation:

where,

are the normality and volume of acid

are the normality and volume of base

We are given:

Putting values in above equation, we get:

Hence, the volume of sulfuric acid required is 4.5 L.

the answer is d.) potassium