How many moles of baf2 are soluble in 250ml of sodium fluoride (naf)? concentration of naf = 0.12 mol/
pksp of baf2 = 5.8

0.0000278 moles of barium fluoride are soluble in 250ml of sodium fluoride.

Explanation:

Concentration of sodium fluoride (NaF) = 0.12 mol/L

1 mole of NaF gives 1 mole of fluoride ions.

Concentration of fluoride ions from NaF=

Concentration of barium fluoride:

of barium fluoride = 5.8

Solubility product of barium fluoride :

               S      (2S+ 0.12)

Total Concentration of barium ions in a final solution = S

Total Concentration of fluoride ions in a final solution= (2S+ 0.12)

An expression of is given as:

Since, barium fluoride is sparingly soluble salt. Value of S will be small so we can neglect values

Calculating for S;

S = 0.00011 mol/L

According to reaction , 1 mol of barium fluoride gives 1 mole of barium ion.Then 0.00011 barium ions will obtained from 0.00011 mol/L of barium fluoride solution.

So the concentration of barium fluoride is 0.00011 mol/L.

Volume of the solution = 250 ml = 0.250 L

n = 0.0000278 mol

0.0000278 moles of barium fluoride are soluble in 250ml of sodium fluoride.

explanation:

venn diagram is pictorial representation with of circles showing the relation between two finite sets or things. the intersection part of two circles conveys the relation present in between those sets or things.

here in the venn diagram of sand and salt two circles represent sand and salt. but the area falling under the intersection of these circle represents the mixture of sand and salt.

so, in a venn diagram the mixture will be placed in a middle that is in between the intersection of two circles.