Draw and label your model of atp: draw and label your model of adp:
draw and label your model of amp:
molecules i created are
and
1. in this activity, you modeled the groups that make up atp, adp, and amp. what atoms are found in the phosphate group?
2. of the following groups—adenine, ribose, and phosphate—which are changed during the processes that convert among atp, adp, and amp? which group or groups does not change?
3. which bond is broken when energy is released?
4. when energy is added, which bond is formed?
5. in steps 8 and 9, you imagined that energy was added to the molecule. what processes would occur in the cell to add this energy?

its adenine, ribose, and phosphate hope this (:

explanation:

#1:

a phosphate group is just a phosphorus atom bound to four oxygen atoms, but it has many important roles. along with sugars and bases, it makes up nucleic acids, like dna and rna. as part of energy carriers, like atp, it provides energy for moving our muscles.

#2: adenine stays unchanged and phosphate and ribose change.

#3: energy can be released or absorbed when various chemical bonds form or are broken.

#4: exothermic reactions release energy in the form of heat whereas endothermic reactions absorb energy.

#5:

when energy is needed by the cell, it is converted from storage molecules into atp. usually only the outer phosphate is removed from atp to yield energy. when this occurs atp is converted to adenosine diphosphate (adp), the form of the nucleotide having only two phosphates.

linda: 3 ; laura: 15

step-by-step explanation:

note that linda + laura's age is 18, and that linda is 12 years younger than her sister.

let "linda" = x , "laura" = y:

x + y = 18

x = y - 12

first, plug in y - 12 for x in the first equation:

(y - 12) + y = 18

simplify.

2y - 12 = 18

isolate the variable (y). note the equal sign, what you do to one side, you do to the other. do the opposite of pemdas. first add, then divide.

2y - 12 (+12) = 18 (+12)

2y = 18 + 12

2y = 30

(2y)/2 = (30)/2

y = 30/2

y = 15

next, plug in 15 for y in the second equation (the other equation would work too).

x = y - 12

x = (15) - 12

x = 3

linda's age is 3, laura's age is 15.

~

yes it is balanced