A20g sample of iron at a temperature of 120oc is placed into a container of water. there are 300 milliliters of water in the container at a temperature of 30oc. ciron=0.444jg∘c cwater=4.184jg∘c rhowater=1gml 10. what is the final temperature of the water?

30.63 °C will be the final temperature of the water.

Explanation:

Heat lost by iron will be equal to heat gained by the water

Mass of iron =

Specific heat capacity of iron =

Initial temperature of the iron =

Final temperature = =T

Volume of water = 300 ml

Density of water = 1 g/mL

Mass of water=

Specific heat capacity of water=

Initial temperature of the water =

Final temperature of water = =T

On substituting all values:

we get, T =  30.63°C

30.63 °C will be the final temperature of the water.