Iron(iii) oxide reacts with carbon monoxide according to the equation: fe2o3(s) + 3 co(g) → 2 fe(s) + 3 co2(g) a reaction mixture initially contains 22.95 g fe2o3 and 15.91 g co. assume that the reaction will progress to 100% completion. what mass (in g) of the excess reactant is leftover?

Explanation:

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In this case, the first step is to compute the moles of the reacting both iron (III) oxide and carbon monoxide as follows:

Now, we can take the reacting iron (III) oxide's moles in order to compute the actual consumed carbon monoxide's moles that would completely react with the iron (III) oxide's moles as follows:

Thus, since there are more available than consumed moles of carbon monoxide, we conclude that the iron (III) oxide is the limiting reagent, in such a way the leftover of carbon monoxide turns out into:

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c. because step up transformer steps up the input voltage i.e increases the input voltage  

the number of turns are greater on the secondary side of step up transformer  

transformer does not handle dc current

i think it's c. i'm not sure but i think so.