Asolution of cacl₂cacl₂ in water forms a mixture that is 31.0%31.0% calcium chloride by mass. if the total mass of the mixture is 650.5 g,650.5 g, what masses of cacl₂cacl₂ and water were used?

There is used 201,655 grams CaCl2 and 448,845 grams of water (H2O)

Explanation:

w% = m(CaCl2) / m(total) x 100%

-> (m(Cacl2) = m(total) x w% ) / 100 %  

-> m(CaCl2) = (650,5g x 31%) / 100%  = 201,655g

Total mass : m(total) = m(CaCl2) + m(H2O)

-> m(H2O) = m(total) - m(CaCl2)

->m(H2O) = 650,5g - 201,655g  = 448,845g