Achemistry student needs 60.00 g of butanoic acid for an experiment. he has available 120. g of a 36.9% w/w solution of butanoic acid in ethanol. calculate the mass of solution the student should use. if there's not enough solution, press the "no solution" button.

There is no solution for the required amount of butanoic acid.

Explanation:

We are given:

Mass of butanoic acid needed = 60.00 grams

36.9 % w/w butanoic acid solution

This means that 36.9 grams of butanoic acid is present in 100 grams of solution

Applying unitary method:

If 36.9 grams of butanoic acid is present in 100 grams of solution

So, 60.00 grams of butanoic acid will be present in =

As, the given amount of solution is less than the required amount.

Hence, there is no solution for the required amount of butanoic acid.