The rate of decomposition of n2o5 in ccl4 at 317 k has been studied by monitoring the concentration of n2o5 in the solution. 2 n2o5(g) → 4 no2(g) + o2(g) initially the concentration of n2o5 is 2.36 m. at 177 minutes, the concentration of n2o5 is reduced to 2.16 m. calculate the average rate of this reaction in m/min.

Average rate of reaction is 0.000565 M/min

Explanation:

Applying law of mass action for the given reaction:

Average rate =

Where, represents average rate of disappearance of , represents average rate of appearance of and represents average rate of appearance of

Here, =

So average rate of reaction = " alt="-\frac{1}{2}\frac{[N_{2}O_{5}]}{\Delta t}" />" /> =

answer: the value of enthalpy change will be -152.80 kj.

solution:

pressure = 1atm , temperature = = 298 k

given that pressure and temperature are same in both gases , the number of moles of both gases can be determined by the ideal gas equation.

according to reaction 3 moles no are reacting with 1 mol of ,then 0.49 mol of no will react with moles of ozone that is 0.16 moles of ozone. since, no is limiting reagent and is an excessive reagent.

enthalpy change for the reaction between the given volumes of the gases is :