Phosphorus reacts with oxygen to form diphosphorus pentoxide, p2o5 . 4p(s)+5o2(g)⟶2p2o5(s) how many grams of p2o5 are formed when 2.45 g of phosphorus reacts with excess oxygen? show the unit analysis used for the calculation by placing the correct components into the unit-factor slots

The answer to your question is:

Explanation:

2.45 g of Phosphorus

MW P = 31 g

MW P2O5 = 2(31) + 5(16) = 142 g

From the balance reaction

               4 P      ⇒ 2 P2O5

Then     4(31) g P    ⇒  2 (142)  g P2O5

       124g  of P       ⇒  284 g   of P2O5              Rule of three

            2.45g P      ⇒      x

x = 2.45 x 284/124 = 695.8/124 = 5.61 g of P2O5