How much 0.2m hcl can be made from 5.0ml of a 12.0m
hclsolution?

The volume of 0.10 M NaOH required to neutralize 30 ml of 0.10 M HCl is, 30 ml.

Explanation:

According to the dilution law,

where,

= molarity of stock solution = 12.0 M

= volume of stock solution = 5.0 ml

= molarity of dilute solution = 0.2 M

= volume of  dilute  solution = ?

Putting in the values we get:

Therefore, 300 ml of 0.2M HCl can be made from 5.0mL of a 12.0M solution.

consider the reaction below.

 no rx

at 500 k, the reaction is at equilibrium with the following concentrations.

[pci5]= 0.0095 m

[pci3] = 0.020

[ci2] = 0.020 m

what is the equilibrium constant for the given reaction?

0.042

0.42

2.4

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