Conversion of mass to moles a continuous feed to a separation unit is 1,000 kg/h of 45 wt% methanol and 55 wt% water, whose molecular weights are 32 and 18, respectively. compute: (a) feed rate in lbmol/h, and (b) composition in mole fractions.

Total feed rate = 98.3 lbmol/h

methanol mole fraction = 0.315

water mole fraction = 0.685

Explanation:

First of all, it is needed to calculate the feed mass of methanol and water in kg/h.

For methanol:

For water:

Now, change from mass units (kg/h) to moles units (kmol/h and lbmol/h) using simple conversion factors:

For methanol:

For water:

Change units from kmol/h to lbmol/h

For methanol:

For water:

Sum moles of methanol and water in lbmol/h to compute the total feed rate:

Divide both methanol and water moles feed rates by total feed rate:

For methanol:

For water:

End

sorry i was late, but i don't know what assignment your talking about, i'm in flvs as well, im in earth space science. but u are behind pace bc every class should be in the 3's or 4'