A500 ml glass of liquid n-pentane at 283 k is removed from a refrigerator that is located outside on a very hot day in phoenix. the n-pentane slowly equilibrates to the ambient temperature, which is 110 °f. the process occurs at 1 bar. calculate the entropy change of the n-pentane, δsn-c5, the entropy change of the surroundings, δssurr, and the entropy change of the universe, δsuniv. neglect the heat capacity of the container. the normal boiling point for n-pentane is 309.2 k, liquid density is 626 kg/m3 , and heat of vaporization can be taken as 25.79 kj/mol. assume constant cp values ca be used, with a liquid cp value of 169 j/mol-k, and a vapor cp value of 126 j/mol-k.

the correct answer is option d

explanation:

i was wrong its d because they dont use cm when calculating square roots

its going to be mutualism cuz they both benefit from the relationship.

~batmans wife dun dun

c, liquids evaporate, creating a gas

considering the question as per the attachment

here we can see that the radon nuclide has 222 as the atomic mass number and 86 as the atomic number.

when it undergoes nuclear fission it gives polonium which has atomic mass number as 218 and atomic number will be 84 along with a helium nucleus which has 4 atomic mass number and 2 as its atomic number.

222 = 218 + 4 (atomic mass number)

86 = ? + 2; therefore ? = 86-2 = 84.

the atomic mass number of polonium will be 84.