How many moles are in 250.0 ml of a 0.15 m nitric acid solution?

Explanation:

It is given that molarity is 0.15 M and volume is 250.0 ml. As 1 ml equals 0.001 l.

Hence, 250.0 ml = 0.25 l.

Also, molarity is equal to the number of moles present in liter of solution. Therefore, calculate number of moles as follows.

                   Molarity =

                      0.15 M =

             No. of moles = 0.0375 mol

Thus, we can conclude that moles present in given solution are 0.0375.

answer; the numbers of valence electrons in the acetic acid molecule (ch3co2h) is 24;