How many grams of calcium chloride would you need to make 1 l of solution containing 5 ppm calcium (ca)?

Explanation:

The given data is as follows.

           Volume = 1 L,    Concentration of Ca = 5 ppm or 5 mg/L

As 1 mg = 0.001 g so, 5 mg /L will be equal to 0.005 g/l. Molar mass of calcium is 40.078 g/mol.

Hence, calculate molarity of calcium as follows.

           Molarity of Ca =

                                  =

         Molarity of Ca =

Hence, molarity of is . Since, volume is same so, moles of calcium chloride will be .

Thus, we can conclude that mass of will be as follows.

                    (molar mass of = 110.984 g/mol)

               = 0.0138 g

Thus, we can conclude that mass of is 0.0138 g.

a: 45.9 meters

b: 4.29 seconds

step-by-step explanation:

a: h(t)=1/2(-9.8)(3)^2+0(3)+90

h(t)=-4.9(3)^2+90

h(t)=-44.1+90

h(t)=45.9 meters

b: 0=1/2(-9.8)(t^2)+0t+90

0=-4.9t^2+90

-90=-4.9t^2

18.37=t^2

t=4.29 seconds

in the second question, the numbers aren't exact, but they're a close approximation.

l dont know l am s sorry