You have a red ballooe that has a volume of 20 liters, a pressure of 1.5 atmospheres and a temperature of 28 c. what is the volume of the balloon if you change the pressure to 5 atmospheres and change the temperature to s0°c oa.1.07 l ob3.0 l 0.64 l o d. o.42 l

Explanation:

The given data is as follows.

  = 1.5 atm,     = 20 L,   = (28 + 273) K = 301 K

    = 5 atm,     = ?,   = (50 + 273) K = 323 K

Formula to calculate the volume will be as follows.

          =

Putting the given values into the above formula as follows.

        =  

        =  

                  = 0.64 L

Thus, we can conclude that the change in volume of the balloon will be 0.64 L.

you need to take a look at the periodic system in order to sort these elements into pairs that would most likely exhibit similar chemical properties. first, you need to find elements that are found in the same group (groups are vertical in the periodic system), and then to see whether they have the same valence number. if they meet these criteria, they will have similar properties.

the first pair: ne (neon) and kr (krypton), are noble gases found in group 8

the second pair: li (lithium) and k (potassium), found in group 1

the third pair: s (sulfur) and te (tellurium), found in group 6