Calculate the volume of 8,410 g of a substance whose density is 0.71 g/ml. express your answer in milliliters using the correct number of significant figures. do not enter your answer using scientific notation.

12 mL

Explanation:

Density is expressed as mass divided by volume, so the expression can be rearranged to solve for volume:

D = m/V ⇒ V = m/D

V = m/D = (8.410 g)/(0.71g/mL) = 12 mL

a. the law of proportion states the combination of 2 atoms in a specific ratio to produce multiple compounds such as the given statement of question ‘1st compound contains 88.8 % cu ’ indicates 88.8 g of cu is present along with 11.2 g oxygen in 100 g of compound whereas the statement ‘2st compound contains 79.9 % cu ’ indicates 79.9 g of cu is present along with 20.1 g oxygen in 100 g of compound

1st compound contains 88.8 g cu

for cu

m = 63 g /mol

atomic % = 88.8 /63 = 1.42

for o

m = 16 g /mol

atomic % = 11.2 /16 = 0.7

b. the emperical formula of 1st compound is

cu1.4o0.7

cu2o