A1.24g sample of a hydrocarbon, when completely burned in an excess of o2 yields 4.04g co2 and 1.24g h20. draw plausible structure for the hydrocarbon molecule

Plausible structure has been given below

Explanation:

4.04 g of = = 0.0918 moles of

1 mol of contains 1 mol of C atom

So, 0.0918 moles of contains 0.0918 moles of C atom

1.24 g of = = 0.0689 moles of

1 mol of  contain 2 moles of H atom

So, 0.0689 moles of contain of or 0.138 moles of

Moles of C : moles of H = 0.0918 : 0.138 = 2 : 3

Empirical formula of hydrocarbon is

So, molecular formula of one of it's analog is

Plausible structure of has been given below.