Calculate the concentration of a bottle of wine contains 12.9% ethanol by volume. the density of ethanol (ch3oh) is 0.789 g/cm ethanol in wine in terms of mass percent and molality mass percent molality =

The mass percentage of the solution is 10.46%.

The molality of the solution is 2.5403 mol/kg.

Explanation:

A bottle of wine contains 12.9% ethanol by volume.

This means that in 100 mL of solution 12.9  L of alcohol is present.

Volume of alcohol = v = 12.9 L

Mass of the ethanol = m

Density of the ethanol ,d=

Mass of water = M

Volume of water ,V= 100 mL - 12.9 mL = 87.1 mL

Density of water = D=1.00 g/mL

Mass percent

Molality :

M = 87.1 g = 0.0871 kg (1 kg =1000 g)

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