I2 is produced by the reaction of 0.4235 mol of cucl2 according to the following equation: 2cucl2+4ki 2cui+4kcl+i2

React with 0.847 mol of KI

Produce:

0.4235 mol of CuI

0.847 mol of KCl

0.21175 moles de I2

Explanation:

2CuCl2 + 4KI    produce 2CuI + 4KCl  + I2

The stoichiometric coefficients give us the relationship in moles:

2 mol of CuCl2 react whit4 mol of KI

0.4235   mol of CuCl2 react whit...X=   0.847mol of KI

2 mol of CuCl2 produce2 mol of CuI

0.4235   mol of CuCl2 produceX=0.4235 mol of CuI

2 mol of CuCl2 produce4 mol of KCl

0.4235   mol of CuCl2 produceX= 0.847 mol of KCl

2 mol of CuCl2 produce 1 mol of I2

0.4235   mol of CuCl2 produceX= 0.21175 moles de I2

If you need to know the mass that is produced you just have to multiply the moles by the molecular mass